Yes, there is a method for determining divisibility by 11, which involves checking the alternating sum of the digits in a number. To do this, subtract the sum of the digits in the odd positions from the sum of the digits in the even positions. If the result is either 0 or divisible by 11, then the original number is also divisible by 11. This method can also be used to directly divide a number by 11, but it may require further calculations to find the quotient and remainder.
The answer depends on what you are dividing by 11.
You get the answer be dividing 9 by 11. That works out to be 81.8%.
no
22/11 = 2 33/11 = 3 44/11 = 4 ..and so on. You have to divide 11 by a number that is a multiple of 11.
The quotient of 55 and 5 is 11. This is calculated by dividing 55 by 5, which equals 11.
The answer depends on what you are dividing by 11.
The empirical formula is the smallest unit which shows the different atoms in their correct ratios. You find it by taking out any common factor from the numbers. In this case all three numbers divide by 11, so the empirical formula is CH2O. In practice, we usually determine the empirical formula from experiment (hence the name), then use it with other information to derive the molecular formula.
You get the answer be dividing 9 by 11. That works out to be 81.8%.
the formula for averaging anything is addition of all figures and then dividing by the number of numbers.
The empirical formula of C3H6O3 is CH2O. This is obtained by dividing the subscripts in the molecular formula by the greatest common factor.
no
-11 degrees Fahrenheit converts to -23.889 Celsius. The Celsius temperature can be found by dividing the Fahrenheit temperature by 1.8.
To find the empirical formula, we need to simplify the subscripts in the molecular formula Se₃O₉ by dividing them by their greatest common divisor. The greatest common divisor of 3 and 9 is 3. Dividing both subscripts by 3 gives us Se₁O₃. Therefore, the empirical formula for the molecule with the molecular formula Se₃O₉ is SeO₃.
The empirical formula of N3P3Cl6 is NPCl2. This is determined by dividing all the subscripts in the formula by the greatest common factor, which is 3 in this case.
22/11 = 2 33/11 = 3 44/11 = 4 ..and so on. You have to divide 11 by a number that is a multiple of 11.
The possible biggest remainder when dividing any number by 12 is 11. This is because when dividing any number by 12, the remainder can range from 0 to 11, with 11 being the largest possible remainder. This is because after dividing by 12, the remainder can never exceed 11, as it would then be the same as or larger than the divisor, which is 12.
All carbohydrates have this empirical formula. CH2O