answersLogoWhite

0

No. Say your matrix is called A, then a number e is an eigenvalue of A exactly when A-eI is singular, where I is the identity matrix of the same dimensions as A. A-eI is singular exactly when (A-eI)T is singular, but (A-eI)T=AT-(eI)T =AT-eI. Therefore we can conclude that e is an eigenvalue of A exactly when it is an eigenvalue of AT.

User Avatar

Wiki User

14y ago

Still curious? Ask our experts.

Chat with our AI personalities

ReneRene
Change my mind. I dare you.
Chat with Rene
EzraEzra
Faith is not about having all the answers, but learning to ask the right questions.
Chat with Ezra
SteveSteve
Knowledge is a journey, you know? We'll get there.
Chat with Steve

Add your answer:

Earn +20 pts
Q: Is there exist a matrix whose eigenvalues are different that of its transpose?
Write your answer...
Submit
Still have questions?
magnify glass
imp