don't know if I understand your question, but: there are no numbers that are both cube numbers and prime numbers 8 is a factor of 16 that is a cube number (2^3) 2 is a factor of 16 that is a prime number
It is the cube of a prime number.
Yes. For example 3 is the cube of cuberoot(3). However, by definition, a prime number cannot be a PERFECT cube.
All numbers have cube roots (not necessarily integral cube roots) so every prime has cube roots.
No.
don't know if I understand your question, but: there are no numbers that are both cube numbers and prime numbers 8 is a factor of 16 that is a cube number (2^3) 2 is a factor of 16 that is a prime number
Three.Three.Three.Three.
5 and 8
It is the cube of a prime number.
Yes. For example 3 is the cube of cuberoot(3). However, by definition, a prime number cannot be a PERFECT cube.
The three prime numbers on the cube are: 2 3 and 5 so the probability is 3/6 or 1/2 simplified
All numbers have cube roots (not necessarily integral cube roots) so every prime has cube roots.
Sure, honey, let me break it down for you. No, a prime number cannot be a perfect cube because a prime number is only divisible by 1 and itself. And let me tell you, a perfect cube is the result of multiplying a number by itself three times, so a prime number ain't gonna fit that bill. So, in short, a prime number and a perfect cube are like oil and water - they just don't mix, darling.
It doesn't matter if you know that the largest three-digit prime number is 997 or that its cube root is 9.98998998. If you include zero in the whole numbers, the answer will be zero.
No.
2, 3 and 5 are prime so P = 0.5
The cube root of this number is 1 more than the smallest prime?