False.
y=3x is a direct variation in that y varies directly with x by a factor of 3. Any linear equation (a polynomial of degree 1, which is a polynomial equation with a highest exponent of 1), is a direct variation of y to x by some constant, and this constant is simply the coefficient of the "x" term. Other examples: y=(1/2)x is a direct variation, and the constant of variation is 1/2 y=-9x is a direct variation, and the constant of variation is -9
1
It is -4.
No, it is not a direct variation.
An equation is a true statement. [ 75 + 4 = -2 ] is a false statement.
y=3x is a direct variation in that y varies directly with x by a factor of 3. Any linear equation (a polynomial of degree 1, which is a polynomial equation with a highest exponent of 1), is a direct variation of y to x by some constant, and this constant is simply the coefficient of the "x" term. Other examples: y=(1/2)x is a direct variation, and the constant of variation is 1/2 y=-9x is a direct variation, and the constant of variation is -9
y = kx: 10 = 37k so k = 10/37 and y = 10x/37
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a varies directly as b and a = 12 when b = 4. What is the constant of variation?
If a statement includes an "equals" sign ( = ) then the statement is an equation. By the way . . . it may or may not be a true statement. "10 equals 120" is not true.
It is -4.
No, it is not a direct variation.
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If y and x are related inversely, then the equation for y can be said to be:y = k/xTo find the constant k, substitute 12 for y and 6 for x (a pair of values that are known to satisfy the equation).y = k/x12 = k/612 X 6 = k72 = kThe value of the variation constant k is 72.
There is only one equation that is given in the question and that equation is not a direct variation.
It means if it is the constant rate of a number kind of like a direct variation. Like if you say 10 divided by 5 it equals 2 and if you say 4 divided by 2 it equals 2 so that's constant I hope I could help you
If P varies directly with the square of Q then the equation would be in the form of P = kQ2, where k is the constant of variation so the new equation would be: P = 6Q2, so when Q = 12 we have P=6*122, or P = 864