-35y-134 = -29 -35y = 134-29 -35y = 105 y = -3
no.
5x/7
Multiply the given fraction by 7y/7y. That's the same as ' 1 ',and it'll give you the denominator of 35y .
With great difficulty, do you mean 35y = 9y-2? If so then the solution is simple: 35y = 9y-2 35y = (32)y-2 35y = 32y-4 Divide both sides of the equation by 3 to eliminate the integers 5y = 2y-4 5y-2y = -4 3y = -4 Divide both sides by 3 to find the value of y y = -4/3 Substituting into the original equation: 35y = 6.594648241 x 10-4 9y-2 = 6.594648241 x 10-4 Therefore: y = -4/3 is correct.
-35y-134 = -29 -35y = 134-29 -35y = 105 y = -3
3x+y=5(4x-7y)=-10 3x+y=20x-35y=-10 -3x -3x y=17x-35y=-10 -y -y 17x-36y=-10 sorry but that's as far as i could get :(
no.
5x/7
2x/5
Multiply the given fraction by 7y/7y. That's the same as ' 1 ',and it'll give you the denominator of 35y .
With great difficulty, do you mean 35y = 9y-2? If so then the solution is simple: 35y = 9y-2 35y = (32)y-2 35y = 32y-4 Divide both sides of the equation by 3 to eliminate the integers 5y = 2y-4 5y-2y = -4 3y = -4 Divide both sides by 3 to find the value of y y = -4/3 Substituting into the original equation: 35y = 6.594648241 x 10-4 9y-2 = 6.594648241 x 10-4 Therefore: y = -4/3 is correct.
-38y - 39x (Is that what you were asking for?)
The 'answer' is usually the number for 'y' that makes the whole statement true.Let's look for it. Actually, the way this works, I'll look for it, while you just watch:-4y + 7 = 35y - 6Add 4y to each side:7 = 39y - 6Add 6 to each side:13 = 39yDivide each side by 39:13/39 = 1/3 = yI think we've found it.
To find an expression equivalent to -28xy 35y, we can first simplify by multiplying the coefficients -28 and 35 to get -980. Then, we multiply the variables x and y to get xy^2. Therefore, the expression equivalent to -28xy 35y is -980xy^2.
The answer is (2y+3)/(7y-1) but I don't understand why the y stays if y^2 - y^2 equals 0 since the y's cancel out. Please help me understand.
4x - 5y = 4 & 6x - 7y = 10 This is a pair of simultaneous equations. Re-write as 4x - 5y = 4 6x - 7y = 10 To find the value of 'x; we need to eliminate 'y' To do this multiply the top eq'n by '-7' and the bottom equation by '5' . This brings the coefficients of 'y' to the same value, but one is plus(+) and the other is negative(-). Hence -28x + 35y = -28 30x - 35y = 50 Add the two eq'ns, this will eliminate 'y' 2x = 22 x = 11