Factors are (7y - 3)(7y - 2) so it's not a perfect square.
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-35y-134 = -29 -35y = 134-29 -35y = 105 y = -3
no.
5x/7
Multiply the given fraction by 7y/7y. That's the same as ' 1 ',and it'll give you the denominator of 35y .
With great difficulty, do you mean 35y = 9y-2? If so then the solution is simple: 35y = 9y-2 35y = (32)y-2 35y = 32y-4 Divide both sides of the equation by 3 to eliminate the integers 5y = 2y-4 5y-2y = -4 3y = -4 Divide both sides by 3 to find the value of y y = -4/3 Substituting into the original equation: 35y = 6.594648241 x 10-4 9y-2 = 6.594648241 x 10-4 Therefore: y = -4/3 is correct.