Good news! You don't have to do anything. [ x-3 = 2 ] is already a linear equation, and x=5 .
Yes.
4
A linear equation is the equation of a line and that consists of an infnite number of points. What you have, in x = -4 and y = -1/3, is a single point. A single point is not a line and so there cannot be a linear equation (suitable for a line) to represent a point.
no, because xx=x squared, and x squared is not linear
Good news! You don't have to do anything. [ x-3 = 2 ] is already a linear equation, and x=5 .
Yes.
4
It is a linear equation in one variable, x. The solution to the equation is x = 6.4
A linear equation is the equation of a line and that consists of an infnite number of points. What you have, in x = -4 and y = -1/3, is a single point. A single point is not a line and so there cannot be a linear equation (suitable for a line) to represent a point.
One linear equation in 3 unknowns cannot have an answer.
no, because xx=x squared, and x squared is not linear
The value of x works out as -3
The equation is linear and so has no vertex.
It's a simple linear equation in 'x'. It's not true unless x = 3 .
"y x 2 2x -3 is not any kind of equation because it does not have an equals sign (=).
-3