yes
As a polynomial in standard form, x plus 5x plus 2 is 6x + 2.
-2 and -6
(x + 5)(x + 2)
To determine the relationship between ( (x - 2) ) and the polynomial ( 2x^3 + x^2 - 3 ), we can perform polynomial division. If ( (x - 2) ) divides the polynomial evenly, then ( (x - 2) ) is a factor of the polynomial. Alternatively, we can evaluate the polynomial at ( x = 2 ); if the result is zero, it confirms that ( (x - 2) ) is a factor. In this case, substituting ( x = 2 ) gives ( 2(2)^3 + (2)^2 - 3 = 16 + 4 - 3 = 17 ), indicating that ( (x - 2) ) is not a factor of the polynomial.
X2 - X - 2(X + 1)(X - 2)===============(X + 1) is a factor of the above polynomial.
As a polynomial in standard form, x plus 5x plus 2 is 6x + 2.
-2 and -6
(x + 5)(x + 2)
(x + 1)(x + 2)
To determine the relationship between ( (x - 2) ) and the polynomial ( 2x^3 + x^2 - 3 ), we can perform polynomial division. If ( (x - 2) ) divides the polynomial evenly, then ( (x - 2) ) is a factor of the polynomial. Alternatively, we can evaluate the polynomial at ( x = 2 ); if the result is zero, it confirms that ( (x - 2) ) is a factor. In this case, substituting ( x = 2 ) gives ( 2(2)^3 + (2)^2 - 3 = 16 + 4 - 3 = 17 ), indicating that ( (x - 2) ) is not a factor of the polynomial.
The polynomial IS written in descending order.
x + 12x + 20 = (x + 10)(x + 2)
X2 - X - 2(X + 1)(X - 2)===============(X + 1) is a factor of the above polynomial.
(x+4)(x-2)
It is (x+2)(x+9) when factored
(x-2)(x-3)
False