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Looking at the function:
x2 + 12x + 28
We know that in order to factor it, we would need two numbers whose product is equal to 28 and whose sum is equal to twelve. We know they must both be positive, as both their sum and their product are positive. That means our possible numbers to combine are all the positive factors of 28:
1, 2, 4, 7, 14, 28
As it happens, no two of these will add up to 12, which tells us that yes, the original polynomial is prime.
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What is the factorization of the trinomial -x2 plus 12x plus 28?
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
12x-28 equals -63 plus 7x?
12x - 28 = 7x - 63Subtract 7x from each side:5x - 28 = -63Add 28 to each side:5x = -35Divide each side by 5:x = -7
What is the answer to x squared minus 11x plus 28 equals 0?
x = -28 / -11^2
What is the product of the prime factor 28?
I think you misworded your question. I am not exactly sure what you are looking for. If you want to know the prime factorization of the number 28, it is, 2^2 * 7. That is two squared times seven.
What is the prime factorization of the number 28?
2 x 2 x 7 or 2 squared x 7
