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Equations: 3x-5y = 16 and xy = 7 Solutions: (7, 1) and (-5/3, -21/5)
its 5 because if y is 3 then u have to ask yourself wat times 3 + 7 is 22
According to the laws of exponents, xy times xz = xy+z. Therefore, 27 x 22 = 2(7+2) = 29 = 512.
If 3x -5y = 16 and xy = 7 then by combining both equations into a single quadratic equation and solving it then the points of intersection are at (-5/3, -21/5) and (7, 1)
We havey = 2x + 1 = 2(4y-2) + 1 = 8y - 3 iff 7y = 3 iff y = 3/7 iff x = 4y - 2 = 12/7 - 2 = -2/7(using "iff" for the double-arrow "is equivalent to" symbol which my PC won't copy).Thus xy = (-2/7)(3/7) = -6/7.