No. If by "yx-2", you mean "y times x minus two", then this will give you "y = 10/x", which is a curve that approaches infinity as x approaches 0, and which approaches 0 as x approaches infinity (dy/dx = -10/x2).
If on the other hand, you mean "y times x to the power of negative two", then solving for y gives you "y = 8/x2", which will give you a similar looking curve, but which approaches 0 at a faster pace (dy/dx = -16/x3)
It is a linear equation in one variable, y.
8
5a - 10 = 4a + 8 is a linear equation in one variable.
No, y=8 is a fixed value. A linear equation would look something like y=x+8 - That would produce a straight line graph if the values of x & y were plotted against each other on a graph.
No it is a linear one. X^2 = quadratic, x = linear. So if the equation doesn't have an x squared, then it is not quadratic.
Yes.
yes it is one
Yes.
It is a linear equation in one variable, y.
It is a linear equation with a single variable, y.
A linear equation in the single variable, e.
8
5a - 10 = 4a + 8 is a linear equation in one variable.
1
It is one linear equation in two unknown variables: e and a.
It is a linear equation in a single variable, w.
No, y=8 is a fixed value. A linear equation would look something like y=x+8 - That would produce a straight line graph if the values of x & y were plotted against each other on a graph.