Unless the rational number is zero, the answer is irrational.
No, but the only exception is if the rational number is zero.
Not if the rational number is zero. In all other cases, the product is irrational.
The product of 0 and an irrational is 0 (a rational), the product of a non-zero rational and any irrational is always irrational.
It is usually irrational but it can be rational if the ration number in the pair is zero. So the correct answer is "either".
When a rational numbers is divided by an irrational number, the answer is irrational for every non-zero rational number.
Such a product is always irrational - unless the rational number happens to be zero.
Unless the rational number is zero, the answer is irrational.
Actually the product of a nonzero rational number and another rational number will always be rational.The product of a nonzero rational number and an IRrational number will always be irrational. (You have to include the "nonzero" caveat because zero times an irrational number is zero, which is rational)
No, but the only exception is if the rational number is zero.
Not if the rational number is zero. In all other cases, the product is irrational.
No. If the rational number is not zero, then such a product is irrational.
The product of 0 and an irrational is 0 (a rational), the product of a non-zero rational and any irrational is always irrational.
Provided that the rational number is not 0, the product is irrational.
It is usually irrational but it can be rational if the ration number in the pair is zero. So the correct answer is "either".
Yes. Any time you multiply a rational number by an irrational number, you get an irrational number - unless the rational number is zero.
Yes, but only if the rational number is non-zero.