To find Julie's average velocity, we first calculate the total distance she ran. Eight laps on a quarter-mile track equals 2 miles (8 laps × 0.25 miles/lap). Since she completed this in eighteen minutes, we convert that to hours: 18 minutes is 0.3 hours. Her average velocity is then distance divided by time, which is 2 miles / 0.3 hours = approximately 6.67 miles per hour.
His velocity was zero - since he's back to where he started. (Try to substitute speed where appropriate.)
Ten laps = 10*.25 = 2.5 miles. 2.5 miles in 15 minutes = 2.5/15 miles per minute = 60*2.5/15 or 10 miles per hour.
The lowest average required to pass typically depends on the specific grading policy of an educational institution or course. Commonly, a passing average is around 60% to 70%. However, some schools may allow for a lower passing average, such as 50%, especially in certain contexts. It's essential to check the specific guidelines set by the institution or instructor.
Math has been in schools as long as there have been schools.
Julie's average velocity was 5 m/s. (Velocity = distance / time = 8 laps x 0.25 miles per lap / 18 minutes = 5 m/s)
His velocity was zero - since he's back to where he started. (Try to substitute speed where appropriate.)
Julie's average velocity was 2 miles per hour. This is calculated by dividing the total distance (2 miles) by the total time (1 hour, as there are 60 minutes in one hour).
To find Julie's average velocity, we first need to determine the total distance she ran. 8 laps around a quarter-mile track is 2 miles (8 laps * 0.25 miles/ lap). Then, we can divide this distance by the total time to get her average velocity, which is 2 miles / 18 minutes = 0.11 miles per minute.
Oh god what's become of our schools?
Average - around 45000
About 8000 dollars on the average.
It depends on where you are located and what kind of cars you want to learn to repair. For instance, schools such as UTI and The Lincoln schools average a $2500 tuition for Mercedes Benz technician training.
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No. I assume you mean Newton's Second Law; this law - in the form it is commonly teached in schools - states that F=ma. Assuming mass is constant, that would make force proportional to acceleration - not to velocity. Acceleration is the rate of change of velocity.
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His velocity was zero - since he's back to where he started. (Try to substitute speed where appropriate.)