Presumably 300 is the perimeter if so then let length be x and the width be 20x:
2(length+width) = perimeter
2(x+20x) = 300
2x+40x = 300
42x = 300
x = about 7.142857143 units
20x = about 142.857429 units
length plus width equals perimetre
The equation to find the volume of a rectangular object is (a) volume equals length times width times height.
a = L x W: area equals length times the width. p = 2L + 2W: perimeter equals 2 times the length plus 2 times the width so L = (p - 2W)/2
To express the statement "length is 4 times the width plus 4" as a formula, you can define the width as ( w ) and the length as ( l ). The formula can then be written as: [ l = 4w + 4. ] This equation indicates that the length (( l )) is equal to four times the width (( w )) plus four.
Assuming you mean a rectangle: use the formula:p = 2(l+w) (i.e., perimeter equals twice length plus width). In this formula, replace p with the known perimeter, and l with the given length, then solve for width.
length plus width equals perimetre
it equals LxL+WxW
The equation to find the volume of a rectangular object is (a) volume equals length times width times height.
a = L x W: area equals length times the width. p = 2L + 2W: perimeter equals 2 times the length plus 2 times the width so L = (p - 2W)/2
2 times length plus 2 times width = perimeterhalf the perimeter of a rectangle
perimeter equals 2 times width plus 2 times length so, perimeter equals 2(3n+2)+2(n-1) = 6n+6+2n-2 = 8n+4.
The length is 16 and the width is 4. 2x16 plus 2x4 equals 40.
The area is the length times the width. The perimeter is two times the length plus two times the width.
The area is the length times the width. The perimeter is two times the length plus two times the width.
To express the statement "length is 4 times the width plus 4" as a formula, you can define the width as ( w ) and the length as ( l ). The formula can then be written as: [ l = 4w + 4. ] This equation indicates that the length (( l )) is equal to four times the width (( w )) plus four.
The area is the length times the width. The perimeter is two times the length plus two times the width.
Assuming you mean a rectangle: use the formula:p = 2(l+w) (i.e., perimeter equals twice length plus width). In this formula, replace p with the known perimeter, and l with the given length, then solve for width.