All factors: 1, 2, 4, 13, 26, 52
-- List all the factors of the first number.-- List all the factors of the second number.-- Find any factors that appear on both lists.-- The highest one of those is the HCF of the two original numbers.
The median as an average this is found by putting all the numbers in numerical order from lowest to highest the number in the middle of the list is the median. For example in the list 3,5,6,9,10,11,12 the number 9 is the median.
the lowest is 10, the highest is 99...
1,3,5,15
If they all have a common denominator, then list them from lowest to highest numerator.
Highest would be a scenario where the best combination of positive factors are all occurring at once. Lowest would be a scenario where all potentially bad things happen.
Don't arrange it at all. Call the first temperature in the list "lowest" and also "highest". Then go down the list. If a temperature is bigger than "highest", re-set "highest" to that temperature, so that further values will be compared with that. Equally, if a temperature is lower than "lowest", re-set "lowest" to that temperature, so that furher values will be also compared with that. Eventually you will reach the end of the data, with "highest" and "lowest" giving the values you want.
All factors: 1, 2, 4, 13, 26, 52
-- List all the factors of the first number.-- List all the factors of the second number.-- Find any factors that appear on both lists.-- The highest one of those is the HCF of the two original numbers.
Oh, dude, like, the common factors of 50 and 100 are 1, 2, 5, and 10. So, like, if you're trying to find what they both share, it's those numbers. It's not rocket science, just basic math, you know?
To find the highest and lowest elements in a linked list, iterate the list and detect the highest and lowest elements. Details omitted ... list *head; /* pointer to first element */ list *temp; /* temp pointer list *high = null; /* pointer to high element */ list *low = null; /* pointer to low element */ for (temp=head; temp!=null; temp=temp->next) { /* iterate all elements */ if (temp == head ) { /* initial case */ high = low = temp; /* start accumulating results } else { /* otherwise */ if (higher(temp, high) high = temp; /* choose higher */ if (lower(temp, low) low = temp; /* choose lower */ } }
Any number can be the lowest as well the highest of a set only if all the numbers are the same.
All non-zero numbers have factors. These can be written down in a list. That would be known as a list of factors.
In order from highest to lowest, you would have the number MDCLXVI, which is equal to 1666.
The median as an average this is found by putting all the numbers in numerical order from lowest to highest the number in the middle of the list is the median. For example in the list 3,5,6,9,10,11,12 the number 9 is the median.
find all factors of 72