V=h/3 (axa + axb + bxb)
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To calculate the surface area of a truncated pyramid, you first take the surface area of each side. That would be the base time the straight height. If it is a 4 side pyramid with equivelant sides, multiply that answer by 4.
The formula for the volume of a truncated square pyramid with height h, and top edge a cm and bottom edge b cm is V = 1/3*(a2 + ab + b2)*h.
A truncated pyramid has: faces = number_of_edges_round_polygon_of_base + 2 vertices = number_of_edges_round_polygon_of_base x 2 edges = number_of_edges_round_polygon_of_base x 3
A "formula" is some mathematical rule for calculating something you wish to know. So "the formula of the rectangle-base pyramid" will be some expression which tells you something that you want to know about it. Beyond that there is no way anyone can tell you, since you do not say what feature of the pyramid you are thinking about (height, volume, surface area, weight...).
Start with an octahedron in the form of a quadrilateral based dipyramid a regular octahedron is a special case of this). This shape has six vertices - chop these off so as to remove a quadrilateral based pyramid. You will be left with a truncated octahedron. It is an octahedron which has been truncated (shortened) by cutting off its extremities.