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Assuming "y3x 6" is "y=3x+6"The range of 3x+6 is -inf < y < inf.Proof below, a little technicallim(x -> inf)(3x+6)=+inflim(x -> - inf)(3x+6)=-infTherefore, the range is -inf < y < inf.
3 and 9 are the only common integers (Ze {-inf; ..... ; -3; -2;-1;0;1;2;3;4;.......;inf})
Given a function f(x), the domain is all of the numbers you are allowed to put in it (in other words x), and the range is all of the numbers you can get from it (in other words f(x)).Here are a few examples:f(x) = 3x+2D: All real numbers (-inf,inf)R: All real numbers (-inf,inf)f(x) = |x| + 2 (where |x| is the absolute value of x)D: All real numbers (-inf,inf)R: All real numbers greater than or equal to 2 [2,inf)f(x) = 1/(4x^2-1)D: All real numbers except 1/2 and -1/2 (because if you plug in either of those you get 1/0 which is undefined) (-inf,-1/2) u (-1/2,1/2) u (1/2,inf)R: All real numbers greater than or equal to -1 except 0. [-1,0) u (0,inf)
y=(√1)-x2 The domain is the set of numbers that "x" can be. In this equation "x" can be any real number. The domain for this problem would be (-inf,inf) *Inf= Infinity*
it is just one tangent interval except sideways from left to right with domain or (-inf,+inf) and the range of (-pi/2,pi/2)