2,4,8,16
We notice that
each term is the previous term multiplied by '2'.
2 x 1 = 2
2 x 2 = 4
4 x 2 = 8 ( 2x2x2)
8 x 2 = 16 (2x2x2x2)
#et. seq.
Instead of writing a string of '2's' multiplied together, we can write it as
2^1 , 2^2 , 2^3, 2^4 et. seq.
So 'n th' term is 2^n
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The Nth term in the series is [ 2N ] .
2n
If you mean: 2 4 8 16 32 64 it is 2^nth term and so the next number is 128
The nth term is equal to 4n.
It is: -6n+22