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2,4,8,16

We notice that

each term is the previous term multiplied by '2'.

2 x 1 = 2

2 x 2 = 4

4 x 2 = 8 ( 2x2x2)

8 x 2 = 16 (2x2x2x2)

#et. seq.

Instead of writing a string of '2's' multiplied together, we can write it as

2^1 , 2^2 , 2^3, 2^4 et. seq.

So 'n th' term is 2^n

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lenpollock

Lvl 16
2y ago

What else can I help you with?