Assuming 5 cards are drawn, the probability is 1.84689 * 10-5. The odds are 1 time in 54145 times. This can be expressed as a decimal, 0.0000184689 or as a percentage, 0.00184689% . Also, I checked these numbers against Wikipedia Poker probability. They give the probability of 0.0240%, but this is for any four of a kind. For the ace four of a kind, we have to divide by 13, and get 0.001846%. The difference of 0.00000089% is due to roundoff. Explanation: There are 52 cards in a deck. A draw of 5 cards means the number of combinations is: 52!/(5! x 47!) = 2598960 different hands (order of cards doesn't make a difference) Four of a kind = only one combination can form a four of a kind, but since we have 5 cards, one card is anything but an ace (one of 48 cards). So there are 48 combinations that form a 4 of a kind. 48/ 2598960 = 1.84689 * 10-5 I used excel in solving this. The combinations can easily be solved by +fact(52)/(fact(47)*fact(5)) Of course, in poker you can exchange cards which I have not included in the calculations.
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There are four aces out of 52 cards, so 4/52 or 1/13
There are 4 aces in the deck the odds that the first card is an ace is 4/52 or 1/13. The odds the second card is an ace is 3/51 or 1/17 because there are only 3 aces and 51 cards left. The odds that both are aces are 1/13 times 1/17 which is 1/221.
If three aces have already been dealt with, there is only one ace left and 49 cards left. P(4th ace)=1/49 The odds are 1 to 49. It is here assumed that four cards cards are delat one by one and the first three were aces.
The odds of being dealt pocket aces in Texas hold 'em is (4 in 52) times (3 in 51) or 12 in 2652 which, reduced, is 1 in 221.
There are four aces in a deck, one of each suit.