P = 48cm
l2=300 l=sqrt(300) = 10*sqrt(3) ~= 17.32 cm P = 4l = 40*sqrt(3) ~= 69.28 cm
If P = 40 then L + W = 20. The only combination which gives A = 100 is where L and W are both 10, ie the figure is a square of side 10 cm.
The circumference and area of a 21.5 cm diameter circle are:C = 67.54 cmA = 363.1 cm2
if it is a square P = 4 x s P = 4 x 7 cm P = 28 cm You may try below link for other shapes http://www.rillocenter.com/geometry/index.html
Perimeter of the square: P = 4a P = 4 × 7 cm P = 28 cm
The length of each edge is p/4 cm.
P = 60 cm
That depends not only on the shape, but on how large it is. Any type of figure can be scaled so that it has any desired perimeter.Examples:A triangle with sides 1 cm, 2 cm, 6 cmA triangle with sides 1 cm, 2 cm, 5 cmA triangle with sides 2 cm, 3 cm, 4 cmA nonagon (more correctly an enneagon) with all sides 1 cm
P = 48cm
P = 24 cm
P = 20 cm
perimeter=60 cm so one side of the square = Perimeter divided by 4 = P/4 = 60/4 =15 cm area of square = side multiplied by side = S * S = 15 * 15 = 225 sq.cm
P = 4(4) = 16 cm
l2=300 l=sqrt(300) = 10*sqrt(3) ~= 17.32 cm P = 4l = 40*sqrt(3) ~= 69.28 cm
If P = 40 then L + W = 20. The only combination which gives A = 100 is where L and W are both 10, ie the figure is a square of side 10 cm.
The circumference and area of a 21.5 cm diameter circle are:C = 67.54 cmA = 363.1 cm2