So, the objective is to find the equation of the line that passes through the points (2, -7) and (5, 2).
The easiest way to do this would be to use the point-slope equation:
y - y1 = m(x - x1)
2 - 5 = m(-7 - 2)
-3 = m(-9)
m = 1/3
Now that we have the slope, we need to find the y-intercept (b)
y = mx + b
y = (1/3)x + b
or
y - (1/3)x = b
Now substitute in one of the points (2, -7)
-7 - (1/3)2 = b
b = -7.666
So the answer would be:
y = (1/3)x - 7.666
It is: y = -31 and there is no x intercept or slope
It is: y = 5x+6
what is the horizontal line that passes through (-5,6)
The slope intercept form through 23 and 15 would be 5. This is considered as a math equation.
y = -5x+2 in slope intercept form
The slope of a vertical line is undefined and so there cannot be a slope-intercept form of the equation.
It is: y = -31 and there is no x intercept or slope
It is: y = 5x+6
what is the horizontal line that passes through (-5,6)
Points: (4, -2) and (6, -3) Slope: -1/2 Straight line equation: y = -1/2x There is no y intercept.
because right away you can tell the slope and y-intercept
The slope intercept form through 23 and 15 would be 5. This is considered as a math equation.
It is in slope intercept form. The slope is 0 and the y-intercept is -2.
y = -5x+2 in slope intercept form
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
The slope-intercept form of an equation is y = mx + b, where m is the slope and b is the y-intercept. Without the specific equation, it is not possible to determine the values of m and b for the slope-intercept form.
Slope intercept is an equation of the form y=mx+b where m is the slope and b is the y-intercept.