I won't tell you the answer, but here's a hint, you can use each number more than one time...
9945 :)
The significant digits are: 3701; so there are four such digits in the measurement. These are the digits that convey the degree of precision included. Leading zeroes and trailing zeroes do not add such meaning.
IF we use four different digits ,For example 12 , 35. 98. 72 . when we add two 2 -digits numbers. 12 + 35 =47 98 + 72 =160 72 + 35 = 107 98 + 12 = 110 the least sum we can get 12+ 35 = 47.
10+23 = 33
To find how many counting numbers have four distinct nonzero digits that sum up to 11, we first identify all combinations of four distinct digits (from 1 to 9) that meet this criterion. The possible combinations of digits that add up to 11 are limited, and we can use combinatorial methods to list them. After identifying valid sets, we can calculate the permutations for each set (since the order of digits matters) to get the total count. Upon calculating, we find there are 24 valid combinations yielding 576 distinct numbers.
There are no four odd numbers that will add up to nineteen.
There are no such numbers.
9945 :)
3, 7 and 9. 4 odd digits that add up to 19 would be 9, 9, 0.5, 0.5
2222
nineteen and four tenths
The significant digits are: 3701; so there are four such digits in the measurement. These are the digits that convey the degree of precision included. Leading zeroes and trailing zeroes do not add such meaning.
IF we use four different digits ,For example 12 , 35. 98. 72 . when we add two 2 -digits numbers. 12 + 35 =47 98 + 72 =160 72 + 35 = 107 98 + 12 = 110 the least sum we can get 12+ 35 = 47.
10+23 = 33
You can work this out pretty quick; just assemble the number in parts. We know the number must be odd, so the last digit has to be an odd one. Let's make it three: 3 Now we need to add five more digits that collectively add up to seven (giving us the sum of ten for our six digits. There's no limit of repetition limit, so we can simply say our numbers are 1, 1, 1, 2 and 2: 111223 That's our last six digits that add up to ten. To get four different eight-digit odd numbers, all we have to do is add four combinations of two digits on the beginning: 99111223 98111223 97111223 96111223
Yes and here is one. pick a number between 1-10 times it by nine add the to digits together. the final answer is NINE
72