No
154 is greater, unless 09 is written as '09, meaning 2009.
If you count 00, 01 though to 09 as 2 digit numbers then you have a 19% chance...There are 100 numbers and 19 contain the number 8....08, 18, 28, 38, 48, 58, 68, 78, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 98ANOTHER ANSWERTwo digit numbers start at 10 and continue to 99. Of these 90 numbers, 18 have at least one 8 in it. That gives 18/90 = 20% chance (exactly).
Fabregas
If they have whole numbers before the decimal point, it's easy. The one with the greaterwhole number before the decimal point is the greater number.If neither one has a whole number before the decimal point, then look for the first placeafter the decimal points where their digits are different.If one has more digits than the other, then zeros can be added to the right of the rightmost digit, without changing the value. The number with the greater digit in that place is the greater number.Example: compare .09 and .15 : The first digit that is different is 0 and 1. 1 > 0 so .15 is greater.How about .2 and .23 ? The first digit is 2 in both, .2 doesn't have any more digits, so make it .20, then compare 0 and 3, so .23 is greater.
No
Yes. The zero is only acting as a place holder.
111 111 111 If you multiply 12345679 by any two digit number* where the first digit is less than 9 and the sum of the digits is 9 (eg 36), the answer will consist of a single digit repeated 9 times. This will be the first digit of the two digit number plus 1 (eg multiplying by 36 will create an number consisting of only the digit 3+1 = 4: 12345679 x 36 = 444 444 444). *Multiplying by 9 is multiplying by the "two" digit number "09", giving an answer consisting of the single digit 0+1 = 1 repeated.
The number after 09 (nine) is 10 (ten).
no
No>.<
154 is greater, unless 09 is written as '09, meaning 2009.
its not possible. you can only steal a taunt
not possible Zenit St. Petersburg are not on fifa 09 therefore making it impossible
There are an infinite number of possible answers.For example:.09%.009%.0009%.08%.089%.0899%.01%.019%.001%.0017%0%-100%
If you count 00, 01 though to 09 as 2 digit numbers then you have a 19% chance...There are 100 numbers and 19 contain the number 8....08, 18, 28, 38, 48, 58, 68, 78, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 98ANOTHER ANSWERTwo digit numbers start at 10 and continue to 99. Of these 90 numbers, 18 have at least one 8 in it. That gives 18/90 = 20% chance (exactly).
If they have whole numbers before the decimal point, it's easy. The one with the greaterwhole number before the decimal point is the greater number.If neither one has a whole number before the decimal point, then look for the first placeafter the decimal points where their digits are different.If one has more digits than the other, then zeros can be added to the right of the rightmost digit, without changing the value. The number with the greater digit in that place is the greater number.Example: compare .09 and .15 : The first digit that is different is 0 and 1. 1 > 0 so .15 is greater.How about .2 and .23 ? The first digit is 2 in both, .2 doesn't have any more digits, so make it .20, then compare 0 and 3, so .23 is greater.