Assume 2^k < k! for all n > k here n > 2,
then 2^n = 2^(n - 1)*2 < (n-1)! * n = n!
Done.
Connie and John
To calculate the number of zeros in a factorial number, we need to determine the number of factors of 5 in the factorial. In this case, we are looking at 10 to the power of 10 factorial. The number of factors of 5 in 10! is 2 (from 5 and 10). Therefore, the number of zeros in 10 to the power of 10 factorial would be 2.
832.
yes
SymbolName+addition sign, plus sign-subtraction sign, minus signx or ⋅multiplication sign÷ or /division sign=equal≠not equal<less than>greater than≤less than or equal to≥greater than or equal to#number sign( )parentheses&and (ampersand)%percentπpi|x|absolute value of x√square root!factorial±plus or minusˆcaret - to the power of
It isn't quite clear what you want to calculate. Perhaps you might try to reformulate your question?
To calculate the number of zeros in a factorial number, we need to determine the number of factors of 5 in the factorial. In this case, we are looking at 10 to the power of 10 factorial. The number of factors of 5 in 10! is 2 (from 5 and 10). Therefore, the number of zeros in 10 to the power of 10 factorial would be 2.
832.
yes
SymbolName+addition sign, plus sign-subtraction sign, minus signx or ⋅multiplication sign÷ or /division sign=equal≠not equal<less than>greater than≤less than or equal to≥greater than or equal to#number sign( )parentheses&and (ampersand)%percentπpi|x|absolute value of x√square root!factorial±plus or minusˆcaret - to the power of
Well, isn't that a happy little math problem! When we look at the unit digit of powers of numbers, we focus on the cyclical pattern they follow. The unit digit of 3 raised to any power follows a pattern: 3, 9, 7, 1, and then repeats. So, to find the unit digit of 3 to the power of 34 factorial, we look for the remainder when 34 factorial is divided by 4, which is 2. Therefore, the unit digit of 3 to the power of 34 factorial is 9.
To prove that 2k 2k plus 1-1 by induction is a step by step process. But the induction 2 is not equal to 2 to the power of 0 take away 1.
It isn't quite clear what you want to calculate. Perhaps you might try to reformulate your question?
2 times 739 minus !6 equals 117,743,173,416,535,106
they are all equal
8 to the power of 8 = 8x8x8x8x8x8x8x8 and does not equal 1 but 1 to the power of 8 does equal 1
eight to the second power equal to 64
The equation cannot be proved because of the scattered parts.