91
5q - 3.75 = 26.25 Therefore, 5q = 30 q = 30/5 q = 6
you have to write an algebraic expression. your number can be any thing you want... lets call it (q) the sum means you add the numbers. so... q + 23 the word (IS) in algebra means equal to so... q + 23 = 20 so what number added to 23 will equal to 20 the answer is negative 3 q=-3
xq/f q divided by f is the fraction q/f
The bounds of integration are 10 and 20. The function that we are integrating is Q(t)=4(.96t)=3.84t. So the average value of Q(t) from 10 to 20 is equal to [1/(20-10)]*the integral from 10 to 20 of 3.84t dt. Simplifying, we get .384*the integral from 10 to 20 of t dt. Integrating, we get that the average value = .384(20^2 - 10^2)/2 = .196*(400 - 100) = .196 * 300 = 58.8. The average value in question is exactly 58.8 grams.
91
3/p = 6 p = 3/6 = 1/2 3/q = 15 q = 3/15 = 1/5 p - q = 1/2 - 1/5 p - q = 5/10-2/10 = 3/10
Undefined: You cannot divide by zero
To find p(x) / q(x), we first need to substitute the expressions for p(x) and q(x) into the formula. So, p(x) = 20x^5 - 20x^4 + 24x^2 and q(x) = 4x^2. Therefore, p(x) / q(x) = (20x^5 - 20x^4 + 24x^2) / 4x^2. Simplifying this expression, we get 5x^3 - 5x^2 + 6.
Any rational number (by definition).
Aquit, equal, pique
5q - 3.75 = 26.25 Therefore, 5q = 30 q = 30/5 q = 6
you have to write an algebraic expression. your number can be any thing you want... lets call it (q) the sum means you add the numbers. so... q + 23 the word (IS) in algebra means equal to so... q + 23 = 20 so what number added to 23 will equal to 20 the answer is negative 3 q=-3
22.6
The question has no solution.If Q = 15 then ABQ is a multiple of 15 and so a multiple of 5.Then, if R = 5 then ABQ + R must also be a multiple of 5.Therefore ABQ + R cannot by 2169, which is NOT a multiple of 5.
q + p
Hill Street Blues - 1981 G-Q- 5-20 was released on: USA: 28 March 1985