1:4
1:4
The ratio is 15/60 or .25=25% So 15 is 25% of 60. This is also equal to 1/4. 15/5=3 60/5=12 15/60=3/12=1/4
If two similar rectangles have the widths 16m and 14cm what is the ratio of the perimiters?
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
60 cm = 0.6 m So the ratio is 0.6 m / 4 m = 0.15
1:4
1:4
The ratio is 15/60 or .25=25% So 15 is 25% of 60. This is also equal to 1/4. 15/5=3 60/5=12 15/60=3/12=1/4
If two similar rectangles have the widths 16m and 14cm what is the ratio of the perimiters?
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
60 cm = 0.6 m So the ratio is 0.6 m / 4 m = 0.15
60/10
To form a square using rectangles measuring 6 cm by 15 cm, we need to find the least common multiple (LCM) of the rectangle's dimensions. The LCM of 6 and 15 is 30 cm. A square with an area of 900 cm² (30 cm x 30 cm) can be formed, requiring a total of 30 cm / 6 cm = 5 rectangles along one side and 30 cm / 15 cm = 2 rectangles along the other side, resulting in 5 x 2 = 10 rectangles needed in total.
It is: 4 to 3
I can give the width of one of the rectangles. The first rectangle of area 15 cm2 and length of 5 cm has width of 3 cm. It is impossible to know the width of the other rectangle of area 60 cm2. However, if you had said that the two rectangles were similar, then the dimensions of the second rectangle would be 10 cm X 6 cm. But you didn't say that the two rectangles were similar; so there are infinite possibilities of what the dimensions of the second rectangle might be.
For the first rectangle, (L x W) = (5 x W) = 15, so W = 3 cm.The second rectangle is included in the question just to confuse you.
4*15 cm = 60 cm