In an RLC series circuit, which comprises a resistor (R), inductor (L), and capacitor (C) connected in series, the second-order differential equation can be derived from Kirchhoff's voltage law. It is expressed as ( L \frac{d^2i(t)}{dt^2} + R \frac{di(t)}{dt} + \frac{1}{C} i(t) = 0 ), where ( i(t) ) is the current through the circuit. This equation models the dynamics of the circuit's response to applied voltage, capturing both transient and steady-state behavior. The solution to this equation can reveal underdamped, critically damped, or overdamped responses depending on the values of R, L, and C.
The answer will depend on the nature of the differential equation.
Power dissipated by the entire series circuit = (voltage between its ends)2 / (sum of resistances of each component in the circuit). Power dissipated by one individual component in the series circuit = (current through the series circuit)2 x (resistance of the individual component).
To solve the partial differential equation ( 5U_{xx} - 3U_{yy} e^{(x-y)} \cos(3x + y) = 0 ), you can use the method of separation of variables or look for a particular solution based on the non-homogeneous term. First, identify the characteristic equations associated with the second-order derivatives. Then, utilize appropriate boundary conditions to find the general solution, which may involve Fourier series or transforms depending on the domain and specific conditions of ( U ). Additionally, you might consider numerical methods if an analytical approach proves complex.
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A data series is a collection of data, most likely numbers, that you would use to graph or solve an equation.
If you add a second resistor, the resistance of series circuit will increase.
The Legendre differential equation is the second-order ordinary differential equation(1)which can be rewritten(2)The above form is a special case of the so-called "associated Legendre differential equation" corresponding to the case . The Legendre differential equation has regular singular points at , 1, and .If the variable is replaced by , then the Legendre differential equation becomes(3)derived below for the associated () case.Since the Legendre differential equation is a second-order ordinary differential equation, it has two linearly independent solutions. A solution which is regular at finite points is called a Legendre function of the first kind, while a solution which is singular at is called a Legendre function of the second kind. If is an integer, the function of the first kind reduces to a polynomial known as theLegendre polynomial.The Legendre differential equation can be solved using the Frobenius method by making a series expansion with ,(4)(5)(6)Plugging in,(7)(8)(9)(10)(11)(12)(13)(14)so each term must vanish and(15)(16)(17)Therefore,(18)(19)(20)(21)(22)so the even solution is(23)Similarly, the odd solution is(24)If is an even integer, the series reduces to a polynomial of degree with only even powers of and the series diverges. If is an odd integer, the series reduces to a polynomial of degree with only odd powers of and the series diverges. The general solution for an integer is then given by the Legendre polynomials(25)(26)where is chosen so as to yield the normalization and is ahypergeometric function.The associated Legendre differential equation is(27)which can be written(28)(Abramowitz and Stegun 1972; Zwillinger 1997, p. 124). The solutions to this equation are called the associated Legendre polynomials (if is an integer), or associated Legendre functions of the first kind (if is not an integer). The complete solution is(29)where is a Legendre function of the second kind.The associated Legendre differential equation is often written in a form obtained by setting . Plugging the identities(30)(31)(32)(33)into (◇) then gives(34)(35)
The answer will depend on the nature of the differential equation.
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
Unscrewing any bulb in a series circuit turns them all off. This is the same as opening the switch that controls them.
There are four types of circuit: series, parallel, series-parallel, and complex.
Nothing. That's why it's a parallel circuit. If it was a series circuit, then the first bulb would go out.
A series circuit is actually in series, but a parallel circuit, is Parallel
series circuit
parallel circuit / series circuit / and a short circuit