Consider 2 convex functions g(x) and f(x).
Using property of second derivative test we have:
g(x)'' > 0 and f(x)'' > 0.
We are interested in showing that y(x) = g(x) + f(x) is also convex.
y(x)'' = c*g(x)'' + k*f(x)'', where c and k are positive numbers (where is no convex function those coeficients after diferentiation will give you negative numbers).
Because c, g(x)'', k, f(x)'' are > 0 , we get y(x)'' also >0, hence y(x) is a convex function.
It is a convex quadrilateral, as the remaining angles could be any two angles with a sum of 180 degrees.
yes
Well, it sounds like a plausible statement, and maybe it would be true . But we haveno idea what the graph of two functions is.Perhaps you could graph the sum of two functions, or the difference of two functions,or their product, or their quotient. We believe that if the original two functions areboth continuous, then their sum and difference would also be continuous, but theirproduct and their quotient might not necessarily be continuous. However, we stilldon't know what the "graph of two functions" is.
Take any two points on or inside a body. If every point on the straight line joining the two points lies within the shape, then it is convex. If not, it is non-convex.
It is an indication of an error, or the fact that the triangle is not in the Euclidean plane but on a convex surface.
It is a convex quadrilateral, as the remaining angles could be any two angles with a sum of 180 degrees.
yes
Yes.
A generalization of wavelets that uses vector valued functions as scaling and wavelet functions. The two scale equation contains a sum of matrices instead of sum of scalars.
the union of two convex sets need not be a convex set.
Well, it sounds like a plausible statement, and maybe it would be true . But we haveno idea what the graph of two functions is.Perhaps you could graph the sum of two functions, or the difference of two functions,or their product, or their quotient. We believe that if the original two functions areboth continuous, then their sum and difference would also be continuous, but theirproduct and their quotient might not necessarily be continuous. However, we stilldon't know what the "graph of two functions" is.
Yes. You would have to multiply to change it.
convex and concave
Take any two points on or inside a body. If every point on the straight line joining the two points lies within the shape, then it is convex. If not, it is non-convex.
two divided by one fifth
No, a concave mirror and a convex mirror have different curvatures and focal points. A concave mirror reflects light inward, converging it to a focal point, while a convex mirror reflects light outward, diverging it. They cannot interchange their functions.
It is an indication of an error, or the fact that the triangle is not in the Euclidean plane but on a convex surface.