A rectangle is a two dimensional object: height, width and length are three dimensions.
show me how to get the answer
W = width of rectangle L = length of rectangle A = area of rectangle W x L = A (L+11) x L = A L squared + 11 L - 1302 = 0 solve for L by quadratic equation or by factoring: (L-31)(L +42) = 0 L = 31 W = L+11 = 42
Volume = length times width times height = length x width x height In our case the volume = 20 x 14 x 8 = 2240 cubic feet
The one alternative to find the area of a rectangle is when you are given the length of one diagonal and its slope.
A line segment has length. That is its only dimension. It does not have any width, or height or depth.
The equation for a rectangle is h(height) x w(width) = area . By manipulating the equation we can show that width=area/length. So 132/12=11. This means the width of the rectangle is 11.
The area is the length times the width. The perimeter is two times the length plus two times the width.
I guessed and the answer is 8
Its width is 11.5 cm.Knowing that, it will be easy for you to reproduce the work.
W = width of rectangle L = length of rectangle A = area of rectangle W x L = A (L+11) x L = A L squared + 11 L - 1302 = 0 solve for L by quadratic equation or by factoring: (L-31)(L +42) = 0 L = 31 W = L+11 = 42
Volume = length times width times height = length x width x height In our case the volume = 20 x 14 x 8 = 2240 cubic feet
The one alternative to find the area of a rectangle is when you are given the length of one diagonal and its slope.
A line segment has length. That is its only dimension. It does not have any width, or height or depth.
The area of rectangle is : 952.0
width, depth and height
Square meters show that there is a flat area. We calculate the area by length times width. This is two-dimensional. Cubic meters show that there is a volume. We calculate the volume by length times width times height. That is three-dimensional.
4 cm * 9 cm = 36 square cm.