33z - 4 - 20z - 5 simplified would be 13z - 1.
To simplify the expression (3 - 5(a - 4)), first distribute the (-5) across the terms inside the parentheses: (3 - 5a + 20). Then, combine the constant terms (3 + 20) to get (23 - 5a). Therefore, the simplified expression is (23 - 5a).
3z-5
72xy^(3)
To simplify the expression (6x \cdot 3y \cdot 6z \cdot 3x \cdot 3z \cdot 5y), first multiply the coefficients: (6 \times 3 \times 6 \times 3 \times 3 \times 5 = 4860). Next, combine the variables: (x^2) (from (x \cdot x)), (y^2) (from (y \cdot y)), and (z^2) (from (z \cdot z)). Thus, the simplified expression is (4860x^2y^2z^2).
-47 + 6z = 3z-2-3z -3z-47 + 3z = -2+47 +473z = 45/3 /3z = 15
If you mean: 33z-4-20z-5 then it is 13z-9 when simplified
3z-5
72xy^(3)
4-3 = 1
- - x + 3 = x + 3
Add like terms to like: (2z - 20) + (3z + 5) = (2z + 3z) + (-20 + 5) = 5z - 15 2z is shorthand for z+z, 3z is shorthand for z+z+z, so: 2z + 3z = (z+z) + (z+z+z) = z+z+z+z+z = 5z Or, to put it another way, just add the coefficients: 2z + 3z = (2+3)z = 5z.
-47 + 6z = 3z-2-3z -3z-47 + 3z = -2+47 +473z = 45/3 /3z = 15
3x+3-2x=3 x+3=3 x-0
(3+2i)-(3+2i)
2b
No
don't answer that