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First we have to factor the radicand into square factors (Hint: *The best squares* try 100, 25, 16, 9 and 4. If none of these work, then try other square factors.) 4 is a factor of 28 so we can rewrite √28 as √4x7 Since 4 is a square factor, we take the square root of 4 which is 2. We put the 2 in front of the radical symbol: 2√7 Now, the radicand is 7 which does does not have square factor. Therefore the simplified radical is 2√7 . this is read "2 times the square root of 7"
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How do you simplify the square root of 300?
simplify the square root of 300 divided by the square root of 6
How do you simplify 4 minus the square root of 28?
The given expression is 4 - √28. Since 28 contains a perfect square factor, we can simplify √28 to get: 4 - √(4 * 7) = 4 - √(2² * 7) = 4 - 2√7
How do you simplify square root of 72 and square root of 2?
Well, there technically is not a way to simplify the square root of 2, but the simplified version of the square root of 72 is 6 square root 2
Simplify the square root of 4?
The square root of 4 = 2
Simplified form of the square root of 28?
√28 can be represented as the square root of two or more numbers whose product is 28. V28 = √(4 x 7) √4 = 2, so we can simplify √28 by extracting the portion representing √4. √28 = 2√7
