the equation for compound interest is Pe^(rt)
the principal you want in the end is twice that of the original
12,000
plugging in and solving you get
12,000=6000e^(.13t)
t = 5.33 years
479.26 needs to be invested to get to 2450 after 20 years at 8.5% compound interest.
I suspect that it will be 6.3!
If the rate is 10% interest on a $20,000 loan for two years, interest will be $4,428.06 if compounded continuously. If compounded annually, it would be $4,200.
48.51 years, approx.
556.34
It is approx 8.66%
is given by the formula A = Pe^rt
10001/999900
"How much money should be deposited at 4.5 percent interest compounded monthly for 3 years?"Incomplete question.... to do what?
479.26 needs to be invested to get to 2450 after 20 years at 8.5% compound interest.
I suspect that it will be 6.3!
If 1500 dollars is invested at an interest rate of 3.5 percent per year compounded continuously, after 3 years it's worth $1666.07, after 6 years it's $1850.52, and after 18 years it's worth $2816.42.
At the end of the year the interest is deposited in the account. The next year the interest is figured on the principal plus last year's interest.
If the rate is 10% interest on a $20,000 loan for two years, interest will be $4,428.06 if compounded continuously. If compounded annually, it would be $4,200.
If you opened a savings account and deposited 5000 in a six percent interest rate compounded daily, then the amount in the account after 180 days will be 5148.
48.51 years, approx.
If the interest is simple interest, then the value at the end of 5 years is 1.3 times the initial investment. If the interest is compounded annually, then the value at the end of 5 years is 1.3382 times the initial investment. If the interest is compounded monthly, then the value at the end of 5 years is 1.3489 times the initial investment.