4x2 + 25y2 = 100 (divide each element of both sides by 100)
x2/25 + y2/4 = 1 This is the equation of an ellipse of the form x2/a2 + y2/b2 = 1, whose center is at (0, 0), a = 5, b = 2, and so c = √(a2 - b2) = √19)
Since the major axis is horizontal and it lies on the x-axis, the vertices are 5 units to the left and 5 units to the right of the center (0, 0).
Vertices are (-5, 0) and (5, 0).
The minor axis is vertical and it lies on the y-axis, so the graph of the ellipse crosses the y-axis at the points (0, -2) and (0, 2), since b = 2)
The foci are √19 units to the left and √19 units to the right of the center (0, 0).
The foci are (-√19, 0) and (√19, 0).
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-2x plus 3y equals 1
sixoversix or one
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Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7