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Using some basic properties from physics and some small angle approximations, one can quickly arrive at the formula

T=2π√(L/g)

Where T is the period of a pendulum in seconds, L is its length in meters, and g is the acceleration due to gravity (9.81m/s²). If you square both sides of this equation, you can quickly derive that

T²=4π²*L/g

Then, if you rearrange this so that L is alone on the left hand side, you will find that

L=g*T²/(4π²)

The slope of this line is everything that is multiplying the T² term, or just g/(4π²).

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Q: Slope of period squared vs pendulum length?
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