5x2 - 2y2 = -20
7x2 - y2 = 152
Eq1 - 2*Eq2: -9x2 = -324
so that x2 = 36
Substituting the value of x2 in Eq1: 2y2 = 200 so that y2 = 100
The four solutions are (-6, -10), (-6, 10), (6, -10) and (6,10)
-10
There are two solutions and they are: x = -1 and y = 3
The solution of the system of linear equations ( x = 0 ) and ( y = 0 ) is the single point (0, 0) in the Cartesian coordinate system. This point represents the intersection of the two equations, where both variables are equal to zero. Thus, the only solution is the origin.
To analyze the linear system given by the equations (3x + 6y = 6) and (x + 2y = 12), we can simplify both equations. The first equation can be rewritten as (x + 2y = 2) by dividing by 3. Now we have the system: (x + 2y = 2) (x + 2y = 12) Since both equations cannot be true simultaneously (they represent parallel lines), the system has no solution.
x = 1 and y = 2
x = y = 3
{-1,-2}
If "equations-" is intended to be "equations", the answer is y = -2. If the first equation is meant to start with -3x, the answer is y = 0.2
-1
-10
There are two solutions and they are: x = -1 and y = 3
No solution
Which of the following best describes the solution to the system of equations below?3x + 6y = 10 9x + 18y = 30
7
The solution of the system of linear equations ( x = 0 ) and ( y = 0 ) is the single point (0, 0) in the Cartesian coordinate system. This point represents the intersection of the two equations, where both variables are equal to zero. Thus, the only solution is the origin.
x=3
To analyze the linear system given by the equations (3x + 6y = 6) and (x + 2y = 12), we can simplify both equations. The first equation can be rewritten as (x + 2y = 2) by dividing by 3. Now we have the system: (x + 2y = 2) (x + 2y = 12) Since both equations cannot be true simultaneously (they represent parallel lines), the system has no solution.