y - 4 = 9 y - 4 + 4 = 9 + 4 y = 13
If x = -7, then x3 = -343 so that 2x3 = -686 y = 2 then 15 y = 30 So 2x3 + 15y = -686 + 30 = -656
Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".
3/Y+7\Y=9 =>Y=10\9
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
3x-y=9 y=3x-9
y - 4 = 9 y - 4 + 4 = 9 + 4 y = 13
If x = -7, then x3 = -343 so that 2x3 = -686 y = 2 then 15 y = 30 So 2x3 + 15y = -686 + 30 = -656
Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".
3/Y+7\Y=9 =>Y=10\9
Set x=0, solve for y, which is the y intercept: 0 - 3y = 9 --> y = -3. Set y=0 and solve for x = 9 for x-intercept.
-9
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
x = -1.2, y = -3
y=4x-8y=2x+10Substitute (4x-8) for y in the second equation and solve for x:4x-8=2x+102x=18x=9Now solve for y:y=4(9)-8=28(9,28)
-y + y equals 0.
I feel like I'm doing someone's homework! y/9 + 5 = 0 rearranging: y/9 = -5 y = -5 x 9 y = -45