3x^2 + 7 x =20
3x^2 + 7x - 20 = 0
3(-4)^2 + 7(-4) -20
3(16) -28 -20
48-28-20 = 0
(-4)
3x^2 + 7x =20
3(1.666)^2 + 7(1.666) -20 =0
3(2.78) + 11.66 - 20 =0
8.34 + 11.66 - 20 = 0
(1.666 or 5/3) answers (-4, 5/3)
(3x-4)(x+5)
To solve for x, we'd have to know what this expression equals.
y=16 x= -4
-7m + 20 = -17m - 1010m = -30m = -3
-3x + 5 = 20 -3x = 15 x = -5
3x^2=-20 so x^2=-20/3 this has no real roots but the plus of minus i(square root of 20/3) is a solution if we allow complex numbers.
(3x-4)(x+5)
(20 - x)/5
20
To solve for x, we'd have to know what this expression equals.
y=16 x= -4
-7m + 20 = -17m - 1010m = -30m = -3
68
20 = 400
-3x + 5 = 20 -3x = 15 x = -5
Better formatting is cos(2x+20)=-0.5
(3x - 5)(x + 4)