x2+2x+x0 = 0
Any integer raised to the power of 0 is always 1 so the equation can be arranged as:
x2+2x+1 = 0
When factorised:
(x+1)(x+1) = 0
Therefore: x = -1 and also x = -1
They both have equal roots because the discriminant b2-4ac (22-4*1*1) = 0
no
It is a quadratic equation in X.
Yes it is. The thing that makes it a quadratic equation is that "x squared" in there.
No, It's a a quadratic equation because you have X squared.
It is a quadratic equation.
no
It is a quadratic equation in X.
Yes it is. The thing that makes it a quadratic equation is that "x squared" in there.
It is a quadratic equation in the one variable.
No, It's a a quadratic equation because you have X squared.
The quadratic equation will have two solutions.
It is a quadratic equation.
No. It's a quadratic equation, and it has two solutions.
If it doesn't have an equal sign, then it's an expression, not an equation. The expression 7x2x is quadratic, because it equals 14x², and something is quadratic if it contains the squared exponent ².
It is a quadratic equation in the variable x.
No it is a linear one. X^2 = quadratic, x = linear. So if the equation doesn't have an x squared, then it is not quadratic.
It is a quadratic equation in X, with two real roots.