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The momentum of an object is calculated by multiplying its mass by its velocity. For spaceship 1, the momentum is (200 , \text{kg} \times 0 , \text{m/s} = 0 , \text{kg m/s}). For spaceship 2, the momentum is (200 , \text{kg} \times 6 , \text{m/s} = 1200 , \text{kg m/s}). Therefore, the combined momentum after the collision, when they stick together, is (0 + 1200 = 1200 , \text{kg m/s}).
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Spaceship 1 and Spaceship 2 have equal masses of 150 kg Spaceship 1 has a speed of 0 m s and Spaceship 2 has a speed of 6 m s They collide and stick together What is their speed?
Momentum = (mass) x (velocity), in the same direction as the velocity.Spaceship-1 . . . Momentum = (150) x (0) = 0 kg-m/sec, in some direction.Spaceship-2 . . . Momentum = (150) x (6) = 900 kg-m/sec, in the same direction.Their combined momentum = 900 kg-m/sec, in their common direction.
When Spaceship 1 and spaceship 2 have equal masses of 200 kg spaceship 1 has a speed of 0ms and spaceship 2 has a speed of 6 ms they collide and stick together What is her speed?
To find the speed of the combined masses after the collision, we can use the conservation of momentum. The initial momentum of the system is given by the momentum of spaceship 2, since spaceship 1 is at rest: ( p_{initial} = m_2 \cdot v_2 = 200 , \text{kg} \cdot 6 , \text{m/s} = 1200 , \text{kg m/s} ). After the collision, the two spaceships stick together, so their combined mass is ( 200 , \text{kg} + 200 , \text{kg} = 400 , \text{kg} ). Using the conservation of momentum, ( p_{initial} = p_{final} ), we have ( 1200 , \text{kg m/s} = 400 , \text{kg} \cdot v_{final} ), leading to ( v_{final} = 3 , \text{m/s} ).
Spaceship 1 and Spaceship 2 have equal masses of 300 kg. Spaceship 1 has a speed of 0 ms and Spaceship 2 has a speed of 4 ms. They collide and stick together. What is their speed?
To find the final speed after the collision, we can use the principle of conservation of momentum. The initial momentum of the system is the momentum of Spaceship 2, since Spaceship 1 is at rest: ( p_{initial} = m_2 \times v_2 = 300 , \text{kg} \times 4 , \text{m/s} = 1200 , \text{kg m/s} ). After the collision, the combined mass is ( 300 , \text{kg} + 300 , \text{kg} = 600 , \text{kg} ). Setting the initial momentum equal to the final momentum, we have ( 1200 , \text{kg m/s} = 600 , \text{kg} \times v_{final} ), which gives ( v_{final} = 2 , \text{m/s} ).
If two spaceships have equal masses and one is stationary and one is moving What is their combined speed if they collide and stick together?
The new speed for the combined masses will be one-half the original velocity of the moving spaceship, since the momentum is applied to a mass twice as large.
Spaceship 1 and Spaceship 2 have equal masses of 300 kg Spaceship 1 has a speed of 0 m/s, and Spaceship 2 has a speed of 4 m/s They collide and stick together What is their speed?
To determine the speed of the combined spaceship after the collision, you can use the principle of conservation of momentum. Before the collision, the total momentum of the system is the sum of the momenta of Spaceship 1 and Spaceship 2. Calculate the initial momentum of each spaceship: Spaceship 1: Mass π 1 = 300 m 1 β =300 kg Speed π£ 1 = 0 v 1 β =0 m/s Momentum π 1 = π 1 β π£ 1 = 300 β 0 = 0 p 1 β =m 1 β β v 1 β =300β 0=0 kgΒ·m/s Spaceship 2: Mass π 2 = 300 m 2 β =300 kg Speed π£ 2 = 4 v 2 β =4 m/s Momentum π 2 = π 2 β π£ 2 = 300 β 4 = 1200 p 2 β =m 2 β β v 2 β =300β 4=1200 kgΒ·m/s Total initial momentum: π totalΒ initial = π 1 π 2 = 0 1200 = 1200 Β kg \cdotp m/s p totalΒ initial β =p 1 β +p 2 β =0+1200=1200Β kg\cdotpm/s After the collision, the two spaceships stick together, so their combined mass is: Total mass π = π 1 π 2 = 300 300 = 600 M=m 1 β +m 2 β =300+300=600 kg Let π£ π v f β be the final velocity of the combined spaceship. The total momentum after the collision must be equal to the total momentum before the collision (conservation of momentum): π totalΒ final = π β π£ π p totalΒ final β =Mβ v f β Set this equal to the total initial momentum: 1200 = 600 β π£ π 1200=600β v f β Solve for π£ π v f β : π£ π = 1200 600 = 2 Β m/s v f β = 600 1200 β =2Β m/s So, the speed of the combined spaceship after the collision is 2 2 m/s.
Spaceship 1 and spaceship 2 have equal masses of 300 kg spaceship 1 has a speed of 0 ms and spaceship 2 has a speed of 6 ms If they collide and stick together what is the combined momentum?
1800 kg-m/sec 600 kg x 3 meters/sec (in the direction spaceship 2 was headed). Since the first spaceship had all the initial momentum, only the velocity of the combined mass will change.
Spaceship 1 and Spaceship 2 have equal masses of 150 kg Spaceship 1 has a speed of 0 ms and Spaceship 2 has a speed of ms They collide and stick together What is their speed?
momentum must be conserved momentum = mass*velocity initially momentum = 150*6 +150*0 = 900 kgms-1 final momentum = 300*combinedvelocity = 900 so the final velocity must be 3 ms-1
Spaceship 1 and Spaceship 2 have equal masses of 150 kg Spaceship 1 has a speed of 0 m s and Spaceship 2 has a speed of 6 m s They collide and stick together What is their speed?
Momentum = (mass) x (velocity), in the same direction as the velocity.Spaceship-1 . . . Momentum = (150) x (0) = 0 kg-m/sec, in some direction.Spaceship-2 . . . Momentum = (150) x (6) = 900 kg-m/sec, in the same direction.Their combined momentum = 900 kg-m/sec, in their common direction.
When Spaceship 1 and spaceship 2 have equal masses of 200 kg spaceship 1 has a speed of 0ms and spaceship 2 has a speed of 6 ms they collide and stick together What is her speed?
To find the speed of the combined masses after the collision, we can use the conservation of momentum. The initial momentum of the system is given by the momentum of spaceship 2, since spaceship 1 is at rest: ( p_{initial} = m_2 \cdot v_2 = 200 , \text{kg} \cdot 6 , \text{m/s} = 1200 , \text{kg m/s} ). After the collision, the two spaceships stick together, so their combined mass is ( 200 , \text{kg} + 200 , \text{kg} = 400 , \text{kg} ). Using the conservation of momentum, ( p_{initial} = p_{final} ), we have ( 1200 , \text{kg m/s} = 400 , \text{kg} \cdot v_{final} ), leading to ( v_{final} = 3 , \text{m/s} ).
Spaceship 1 and Spaceship 2 have equal masses of 300 kg. Spaceship 1 has a speed of 0 ms and Spaceship 2 has a speed of 4 ms. They collide and stick together. What is their speed?
To find the final speed after the collision, we can use the principle of conservation of momentum. The initial momentum of the system is the momentum of Spaceship 2, since Spaceship 1 is at rest: ( p_{initial} = m_2 \times v_2 = 300 , \text{kg} \times 4 , \text{m/s} = 1200 , \text{kg m/s} ). After the collision, the combined mass is ( 300 , \text{kg} + 300 , \text{kg} = 600 , \text{kg} ). Setting the initial momentum equal to the final momentum, we have ( 1200 , \text{kg m/s} = 600 , \text{kg} \times v_{final} ), which gives ( v_{final} = 2 , \text{m/s} ).
Spaceship 1 and Spaceship 2 have equal masses of 300 kg Spaceship 1 has an initial momentum magnitude of 600 kg-m/s What is its initial speed?
Momentum = (mass) x (velocity), in the same direction as the velocity.Spaceship-1 . . . Momentum = (200) x (0) = 0 kg-m/sec, in some direction.Spaceship-2 . . . Momentum = (200) x (6) = 1200 kg-m/sec, in the same direction.Their combined momentum = 1200 kg-m/sec, in their common direction.
Spaceship 1 and Spaceship 2 have equal masses of 150 kg Spaceship 1 has a speed of 0 and Spaceship 2 has a speed of 6 They collide and stick together What is their speed?
3 m/s
If two spaceships have equal masses and one is stationary and one is moving What is their combined speed if they collide and stick together?
The new speed for the combined masses will be one-half the original velocity of the moving spaceship, since the momentum is applied to a mass twice as large.
Spaceship 1 and Spaceship 2 have equal masses of 300 kg Spaceship 1 has a speed of 0 m/s, and Spaceship 2 has a speed of 4 m/s They collide and stick together What is their speed?
To determine the speed of the combined spaceship after the collision, you can use the principle of conservation of momentum. Before the collision, the total momentum of the system is the sum of the momenta of Spaceship 1 and Spaceship 2. Calculate the initial momentum of each spaceship: Spaceship 1: Mass π 1 = 300 m 1 β =300 kg Speed π£ 1 = 0 v 1 β =0 m/s Momentum π 1 = π 1 β π£ 1 = 300 β 0 = 0 p 1 β =m 1 β β v 1 β =300β 0=0 kgΒ·m/s Spaceship 2: Mass π 2 = 300 m 2 β =300 kg Speed π£ 2 = 4 v 2 β =4 m/s Momentum π 2 = π 2 β π£ 2 = 300 β 4 = 1200 p 2 β =m 2 β β v 2 β =300β 4=1200 kgΒ·m/s Total initial momentum: π totalΒ initial = π 1 π 2 = 0 1200 = 1200 Β kg \cdotp m/s p totalΒ initial β =p 1 β +p 2 β =0+1200=1200Β kg\cdotpm/s After the collision, the two spaceships stick together, so their combined mass is: Total mass π = π 1 π 2 = 300 300 = 600 M=m 1 β +m 2 β =300+300=600 kg Let π£ π v f β be the final velocity of the combined spaceship. The total momentum after the collision must be equal to the total momentum before the collision (conservation of momentum): π totalΒ final = π β π£ π p totalΒ final β =Mβ v f β Set this equal to the total initial momentum: 1200 = 600 β π£ π 1200=600β v f β Solve for π£ π v f β : π£ π = 1200 600 = 2 Β m/s v f β = 600 1200 β =2Β m/s So, the speed of the combined spaceship after the collision is 2 2 m/s.
Spaceship 1 and spaceship 2 have equal masses of 300kg spaceship 1s has a speed is 0 ms and spaceship 2 has a speed of 4 ms. they collide and stick together. what is their speed?
2 m/s
Spaceship 1 and Spaceship 2 have equal masses of 200 kg Spaceship 1 has a speed of 0 m s and Spaceship 2 has a speed of 6 m s They collide and stick together What is their speed?
3 m/s
Spaceship 1 and Spaceship 2 have equal masses of 300 kg Spaceship 1 has a speed of 0 ms and Spaceship 2 has a speed of 4 ms They collide and stick together What is their speed?
2 m/sec in the direction of travel of Spaceship 2, assuming they are both in frictionless outer space.
