Momentum = (mass) x (velocity), in the same direction as the velocity.Spaceship-1 . . . Momentum = (150) x (0) = 0 kg-m/sec, in some direction.Spaceship-2 . . . Momentum = (150) x (6) = 900 kg-m/sec, in the same direction.Their combined momentum = 900 kg-m/sec, in their common direction.
The new speed for the combined masses will be one-half the original velocity of the moving spaceship, since the momentum is applied to a mass twice as large.
2 m/s
To determine the speed of the combined spaceship after the collision, you can use the principle of conservation of momentum. Before the collision, the total momentum of the system is the sum of the momenta of Spaceship 1 and Spaceship 2. Calculate the initial momentum of each spaceship: Spaceship 1: Mass π 1 = 300 m 1 β =300 kg Speed π£ 1 = 0 v 1 β =0 m/s Momentum π 1 = π 1 β π£ 1 = 300 β 0 = 0 p 1 β =m 1 β β v 1 β =300β 0=0 kgΒ·m/s Spaceship 2: Mass π 2 = 300 m 2 β =300 kg Speed π£ 2 = 4 v 2 β =4 m/s Momentum π 2 = π 2 β π£ 2 = 300 β 4 = 1200 p 2 β =m 2 β β v 2 β =300β 4=1200 kgΒ·m/s Total initial momentum: π totalΒ initial = π 1 π 2 = 0 1200 = 1200 Β kg \cdotp m/s p totalΒ initial β =p 1 β +p 2 β =0+1200=1200Β kg\cdotpm/s After the collision, the two spaceships stick together, so their combined mass is: Total mass π = π 1 π 2 = 300 300 = 600 M=m 1 β +m 2 β =300+300=600 kg Let π£ π v f β be the final velocity of the combined spaceship. The total momentum after the collision must be equal to the total momentum before the collision (conservation of momentum): π totalΒ final = π β π£ π p totalΒ final β =Mβ v f β Set this equal to the total initial momentum: 1200 = 600 β π£ π 1200=600β v f β Solve for π£ π v f β : π£ π = 1200 600 = 2 Β m/s v f β = 600 1200 β =2Β m/s So, the speed of the combined spaceship after the collision is 2 2 m/s.
-- mass -- velocity
The momentum of an object is given by the product of its mass and velocity. Therefore, the momentum of spaceship 1 before the collision is 0 kgm/s and the momentum of spaceship 2 before the collision is 1800 kgm/s. When they collide and stick together, their momenta are added, resulting in a combined momentum of 1800 kg*m/s.
Their speed after the collision will be 0 m/s since Spaceship 1 was stationary and Spaceship 2 had no stated speed. The total momentum before the collision is zero, so the total momentum after the collision will also be zero if they stick together.
Momentum = (mass) x (velocity), in the same direction as the velocity.Spaceship-1 . . . Momentum = (150) x (0) = 0 kg-m/sec, in some direction.Spaceship-2 . . . Momentum = (150) x (6) = 900 kg-m/sec, in the same direction.Their combined momentum = 900 kg-m/sec, in their common direction.
The initial speed of Spaceship 1 can be calculated using the momentum formula: momentum = mass x velocity. Given that the momentum is 600 kg-m/s and the mass is 300 kg, the initial speed of Spaceship 1 is 2 m/s.
3 m/s
The new speed for the combined masses will be one-half the original velocity of the moving spaceship, since the momentum is applied to a mass twice as large.
2 m/s
To determine the speed of the combined spaceship after the collision, you can use the principle of conservation of momentum. Before the collision, the total momentum of the system is the sum of the momenta of Spaceship 1 and Spaceship 2. Calculate the initial momentum of each spaceship: Spaceship 1: Mass π 1 = 300 m 1 β =300 kg Speed π£ 1 = 0 v 1 β =0 m/s Momentum π 1 = π 1 β π£ 1 = 300 β 0 = 0 p 1 β =m 1 β β v 1 β =300β 0=0 kgΒ·m/s Spaceship 2: Mass π 2 = 300 m 2 β =300 kg Speed π£ 2 = 4 v 2 β =4 m/s Momentum π 2 = π 2 β π£ 2 = 300 β 4 = 1200 p 2 β =m 2 β β v 2 β =300β 4=1200 kgΒ·m/s Total initial momentum: π totalΒ initial = π 1 π 2 = 0 1200 = 1200 Β kg \cdotp m/s p totalΒ initial β =p 1 β +p 2 β =0+1200=1200Β kg\cdotpm/s After the collision, the two spaceships stick together, so their combined mass is: Total mass π = π 1 π 2 = 300 300 = 600 M=m 1 β +m 2 β =300+300=600 kg Let π£ π v f β be the final velocity of the combined spaceship. The total momentum after the collision must be equal to the total momentum before the collision (conservation of momentum): π totalΒ final = π β π£ π p totalΒ final β =Mβ v f β Set this equal to the total initial momentum: 1200 = 600 β π£ π 1200=600β v f β Solve for π£ π v f β : π£ π = 1200 600 = 2 Β m/s v f β = 600 1200 β =2Β m/s So, the speed of the combined spaceship after the collision is 2 2 m/s.
3 m/s
2 m/sec in the direction of travel of Spaceship 2, assuming they are both in frictionless outer space.
Some examples of combined words are: breakfast, spaceship, thunderstorm, butterfly. These words are formed by merging two individual words together to create a new word with a specific meaning.
Their combined momentum will be equal to the first boxcar's original momentum before the collision.