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4 students can do 80 math problems in one hour. how many math problems can 8 students do in 3 hours?
Ok, SO if 4 students can do 80 math problems in one hour, each student can do 20 math problems an hour. This is because 80 math problems divided by 4 students/kids is 20, well 80 divided by or / by 4 is twenty. Ok, so each student can do twenty problems an hour, and twenty multiplied by 8 (because there are now eight students doing math problems) is 160. So, that is in one hour. So, then, to, find, how much they can do in 3 hours, multiply this by 3 because 160/h multiplied by 3 is x/3r. so now 160x3 is 480, so 8 students can do 480 math problems in 3 hours.Hope this helps!
What are some of the factors that contribute to students' inability to solve word problems?
Some students have trouble with word problems. They may not fully understand what the question is asking. They may not understand topic. Or they might not be the smartest in word problems. If so , I would consider a tutor.
A math test has two problems The first was solved by 70 percent of the students The second was solved by 60 percent Every student solved at least one of the problems Nine students solved both problem?
.7x-.6x=9, .1x=9, x=9/.1=90 students
What examples of common misconceptions students have when working with positive and negative numbers?
Working with a number line to solve there problems.
What are Venn diagrams and how are they useful?
A picture of a Venn diagram is in the related links. They are useful because they help you map out problems such as "If there are 3 students in math, 5 students in science and 6 students in total, how many are in both math and science?" To this, you can use the Venn diagram to reason that since there seem to be 8 students in total if math and science are separate, there must be 2 students in both classes.
