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Due to the rubbish browser that we are compelled to use, it is not possible to use any super or subscripts so here goes, with things spelled out in detail:

log to base 2a of 2b = log to base a of 2b/log to base a of 2a

= [(log to base a of 2) + (log to base a of b)] / [(log to base a of 2) + (log to base a of a)]

= [(log to base a of 2) + (log to base a of b)] / [(log to base a of 2) + 1]

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Q: Suppose aneq 0. Compute log 2a 2b in terms of a and b.?
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