i have no idea im wondering the same thing.
== == yes. suppose the quad ABCD has AB and CD equal and parallel. Then the triangles ABC and CDA are congruent by SAS axiom; so the quad is a parallelogram
I'm guessing you mean with parallels and a transversal. If this is the case, then find he angle that is either a; supplementary (creating a flat angle, 180 degrees) or b; complimentary (creating a 90 degree angle) subtract the supplementary/complimentary angle from either 180 or 90 and the difference is your answer. Hope I helped! * * * * * More likely the question is concerned with the interior angles of a polygon. If the polygon is irregular then there is no simple answer. An interior angle can have any value. However, if it is a regular polygon then the question can be answered. The sum of all the exterior angles is 360 degrees - irrespective of the number of sides (or vertices). Suppose the polygon has n sides/vertices. Then, since it is regular, each exterior angle is 360/n. Therefore, each interior angle is 180-360/n degrees.
The answer depends on what information you have about the rhombus and on how much mathematics you know. I suppose the simplest is:Area = a^2*sin(x) where a is the length of the sides, and x is an interior angle.
No, suppose is a verb.
Suppose the top face of the pyramid is ABCD with the square EFGH directly below it.Suppose AC and BD meet at P, the apex of the pyramid.Make a cut with a plane through P which is parallel to AB and goes through EF.Make a cut with a plane through P which is parallel to BC and goes through FG.Make a cut with a plane through P which is parallel to CD and goes through GH.Make a cut with a plane through P which is parallel to DA and goes through HE.The result will be the square-based pyramid PEFGH.
I suppose so i dont really know but i know a few interior designer's and they get stressed out a "lot" infact 1 of them went to the doctors about stress control
== == yes. suppose the quad ABCD has AB and CD equal and parallel. Then the triangles ABC and CDA are congruent by SAS axiom; so the quad is a parallelogram
One, unless you suppose they're descending through planes, then infinite. But one that they both occupy.
I'm guessing you mean with parallels and a transversal. If this is the case, then find he angle that is either a; supplementary (creating a flat angle, 180 degrees) or b; complimentary (creating a 90 degree angle) subtract the supplementary/complimentary angle from either 180 or 90 and the difference is your answer. Hope I helped! * * * * * More likely the question is concerned with the interior angles of a polygon. If the polygon is irregular then there is no simple answer. An interior angle can have any value. However, if it is a regular polygon then the question can be answered. The sum of all the exterior angles is 360 degrees - irrespective of the number of sides (or vertices). Suppose the polygon has n sides/vertices. Then, since it is regular, each exterior angle is 360/n. Therefore, each interior angle is 180-360/n degrees.
i suppose it is an hyperbola
Suppose the parallel sides of the trapezium are a and b units where a < b. Then the fraction of the area of the trapezium that is the rhombus is a/[(a+b)/2] = 2a/(a+b).
The answer depends on what information you have about the rhombus and on how much mathematics you know. I suppose the simplest is:Area = a^2*sin(x) where a is the length of the sides, and x is an interior angle.
Suppose the polygon has n sides Then sum of interior angles = (n-2)*180 degrees = 3960 degrees so n-2 = 3960/180 = 22 and so n = 24
The verb form 'to suppose' used for a plural subject is suppose, for example: We suppose... You suppose... They suppose... The students suppose...
That depends on whether the bulbs are wired in series or in parallel.
The present tense of "suppose" is "suppose." For example: "I suppose that she will be here soon."
Any gap in a series circuit causes the whole thing to stop working. That is why houses are wired in parallel with each other, and indeed there are many parallel circuits inside each house.