The numbers are 25 and 4
Explanation:
If A and B are two whole numbers, the product of their
LCM and GCF is equal to their product AB.
So using this we have AB=100
and A+B=29 so
A=29-B
B(29-B)=100
This is a quadratic 29B-B2 -100=0
or
B2 -29B+100=0
(B-25)(B-4)=0
So B=25 and 4.
Now let's check
The gcf 25 and 4 is 1
The LCM is 100
Let the two numbers be x and y. Let suppose that the average of two numbers is 20. Then,x + y = 40 and 40/GCF = 5, where GCF = 40/5 = 8Since LCM is 48 and GCF is 8, the numbers are 16 and 24, whose average is 20 is true.
Product = LCM x GCF = 384, sum = 40. Factors of 384 = 2 x 192, 3 x 128, 4 x 96, 6 x 64, 8 x 48, 12 x 34, 16 x 24 That'll do! The numbers are 16 and 24
The sum of the numbers from 1 through 100 is 5,050.
Look at both of the numbers' prime factors, and put them into a sum. The LCM multiple is the answer you get from that.
16 and 3
40 and 50
40 and 50
You cannot. LCM{2,6,12} = 12 and GCF{2,6,12} = 2 LCM{4,6,12} = 12 and GCF{4,6,12} = 2 The two sets have the same LCM and GCF but, clearly, their sums are different.
The GCF of 6 and 10 is 2.
60 and 36
40 and 50
They are: GCF = 5 and LCM = 325 and the sum is 5+325 = 330
The GCF of 9 and 15 is 3. The LCM is 45.
How about: 12, 16 and 24
The sum is 335.
Let the two numbers be x and y. Let suppose that the average of two numbers is 20. Then,x + y = 40 and 40/GCF = 5, where GCF = 40/5 = 8Since LCM is 48 and GCF is 8, the numbers are 16 and 24, whose average is 20 is true.
The LCM will never be less than the GCF.