The additive inverse of a number divided by twelve is the same as one less than three times its reciprocal What is the number?

Answer 1

Well, honey, let's break it down for you. Let's call the number x. The additive inverse of x divided by twelve is -x/12. And one less than three times its reciprocal is 3(1/x) - 1. So, we have -x/12 = 3/x - 1. Now, solve that bad boy and you'll find your number.

Answer 2

Let's denote the number as x. The additive inverse of x divided by twelve is -x/12. One less than three times its reciprocal is 3(1/x) - 1 = 3/x - 1. Setting these two expressions equal, we have -x/12 = 3/x - 1. Simplifying, we get -x/12 = (3 - x)/x. Cross multiplying gives us -x^2 = 12(3 - x), which simplifies to x^2 + 12x - 36 = 0. Solving this quadratic equation, we find that x = -6 ± 2√13.

Answer 3

Oh, what a lovely little math puzzle we have here! Let's take it step by step. If we call the number "x," the additive inverse of x divided by twelve is -x/12, and one less than three times its reciprocal is 3(1/x) - 1. By setting these two expressions equal to each other and solving for x, we find x = -4. Just like painting a happy little tree, sometimes math can be a fun and peaceful adventure!

Answer 4

6