137 ft
If the base of the elevation is at a distance d from the observer, then the highest point is at a height = d*tan(angle of elevation)
False because if each base angle is 43 degrees then the apex angle must be 94 degrees
No but its apex angle can be a right angle with 2 equal base angles of 45 degrees
tan40=x/100 100tan(40)=83.9m
56 degrees
height = 15 ft base = 20 ft angle of elevation = arctan (15/20) = 36.87 degrees
25 feet
If the base of the elevation is at a distance d from the observer, then the highest point is at a height = d*tan(angle of elevation)
X = 24 / (tan 12o) X = 112.9111 m In a right angled triangle, the lighthouse is the opposite the distance between the ship and lighthouse is the base and the hypotenuse is the captain looking at the top of the lighthouse it is 400.9675876
A simple angle of elevation problem...You want to find out the height of a tree. You measure the distance from you to the base and find that it is 100 feet. You measure the angle of elevation of the top and find that it is 30 degrees. You are six feet tall. How tall is the tree?Answer: The tree is 64 feet tall. Its height is tangent 30 times 100 + 6.
You can use trigonometry to find the angle of elevation. Let x be the distance from the tip of the shadow to the base of the pole and the height of the pole be y. Then, tan(60 degrees) = y/x. Given that the height of the pole is 12 feet, you can solve for x to find the angle of elevation.
20 degrees
55 degrees
If it's an isosceles triangle and the apex angle is 70 degrees then the base angles will each measure 55 degrees
False because if each base angle is 43 degrees then the apex angle must be 94 degrees
No but its apex angle can be a right angle with 2 equal base angles of 45 degrees
tan40=x/100 100tan(40)=83.9m