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Outer radius = a; inner radius = b; then area of the ring = pi (a2 - b2) = 90, where pi = 22/7. In view of a = 9, we have b2 = 81 - [90 x 7 / 22], the positive square root of which gives b.

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Q: The area of a circular ring is 90 if the radius of the outer circle forming the ring is 9 what is the radius of the inner circle of the ring assuming the circles forming the ring have same center?
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