By Pythagoras,
Distance2 = [6 - (-8)]2 + [32 - (-16)]2
= [6 + 8]2 + [32 + 16]2
= [14]2 + [48]2
= 196 + 2304 = 2500
So Distance = sqrt(2500) = 50
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16 with 6 remaining 518 - 6 = 512 = 32 x 16
6/32 simplifies to 3/16
1-16: 6 primes 16-32: 5 primes 32-48: 4 primes
Any two numbers that have a distance of 16 between them, such as 0 and 16, or -16 and 0, or -8 and 8, or 6 and 22.
It is 16/48 = 1/3 but 6/36 = 1/6 But if you mean: 6-36 = -30 and 16-48 = -32 then -30 is greater than -32