The first 5 multiples of 1 are: 1, 2, 3, 4, and 5.
The 3 first multiples of 75 are: 1, 3, and 5.
They are the first three multiples of LCM(5, 9), that is, the first three multiples of 45.
The first 4 multiples of 1 are: 1, 2, 3, and 4.
The odd multiples of 5 end with 5.If there is an even number of odd multiples of 5, their sum ends in 0, meaning their remainder when divided by 10 is 0;If there is an odd number of odd multiples of 5, their sum ends in 5, meaning their remainder when divided by 10 is 5.By "odd multiples of 5 from 1 to 2007 " do you mean:the multiples 1, 3, 5, ..., 2007 of 5?1 = 2 x 1 - 1, 3= 2 x 2 - 1, ..., 2007 = 2 x 1004 - 1 So there are 1004 multiples of 5, which is even so their sum has a remainder of 0 when divided by 10.the numbers between 1 and 2007 which are odd multiples of 5?1 ÷ 5 = 0.2 → first multiple of 5 in the range is 1 x 5 → the first odd multiple = 1 x 5 2007 ÷ 5 = 401.4 → last multiple of 5 in the range is 401 x 5 → the last odd multiple = 201 x 5401 = 2 x 201 - 1 which means there are 201 multiples of 5, which is odd so their sum has a remainder of 5 when divided by 10.As our number system is based on 10, the remainder when dividing by 10 gives the value of the units (last) digit of the original number.All even multiples of 5 end have a units digit of zero and do not affect the units digit of the sum when added; so the question could have included the even multiples of 5 (ie "What is the remainder when the multiples of five...") without changing the final answer.
The first 5 multiples of 1 are: 1, 2, 3, 4, and 5.
The first 5 multiples of 1 are: 1, 2, 3, 4, and 5.
The 3 first multiples of 75 are: 1, 3, and 5.
1, 2, 3, 4, 5.
because 5 is the 1*5 and 1 is the first number.
Since you didn't specify a single number, and all numbers are multiples of themselves, the five smallest multiples are the counting numbers 1 to 5.
The first is 5*1, the second is 5*2 etc. It is easy enough to work these out.
the first 5 multiples of 34 is 34,68,102,136,170 I hope these multiples was helpful if i got a mistake plz answer a new 1 THANKS!!!!!
They are the first three multiples of LCM(5, 9), that is, the first three multiples of 45.
Multiples of 12: 1, 2, 3, 4, 6, 12 Multiples of 5: 1, 5
1 x 5 = 5 3 x 5 = 15
There are only two multiples of five. The multiples are 1 and 5. 5 is a prime number. A prime number is when a number is or can only be multiplied by one or itself. (In this case itself is five.)