Q: The largest prime number that can be written as two of prime numbersr and as the difference of two prime numbers?

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There is no difference. Rational numbers are numbers that can be written as a fraction. Irrational numbers cannot be expressed as a fraction.

Yes it is. Rational numbers are numbers that can be written as a fraction. Irrational numbers cannot be expressed as a fraction.

5 = 2+3 = 7-2

If we use numbers that can be written with only ones and zeros, then we're working with binary numbers. The largest binary number that can be written with seven bits is "127". When you remember to include 'zero', that makes a total of 128 different numbers. The sum of the (smallest + largest) is (0 + 127) = 127 The sum of the (second smallest + second largest) = (1 + 126) = 127 The sum of the (third smallest + third largest) = (2 + 125) = 127 Each sum built in this way is 127, and there are (half of 128) = 64 of them. So the sum of all 128 numbers is (64 times 127) = 8,128

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Related questions

5

Rational numbers are numbers that can be written as a fraction. Irrational numbers cannot be expressed as a fraction.

Rational numbers are numbers that can be written as a fraction. Irrational numbers cannot be expressed as a fraction. All natural numbers are rational.

98

Rational numbers are numbers that can be written as a fraction. Real numbers are any number, including irrationals.

There is no difference. Rational numbers are numbers that can be written as a fraction. Irrational numbers cannot be expressed as a fraction.

Yes it is. Rational numbers are numbers that can be written as a fraction. Irrational numbers cannot be expressed as a fraction.

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A rational number can be written as (one whole number) divided by (another whole number). An irrational number can't.

If we use numbers that can be written with only ones and zeros, then we're working with binary numbers. The largest binary number that can be written with seven bits is "127". When you remember to include 'zero', that makes a total of 128 different numbers. The sum of the (smallest + largest) is (0 + 127) = 127 The sum of the (second smallest + second largest) = (1 + 126) = 127 The sum of the (third smallest + third largest) = (2 + 125) = 127 Each sum built in this way is 127, and there are (half of 128) = 64 of them. So the sum of all 128 numbers is (64 times 127) = 8,128

5 = 2+3 = 7-2

The three largest numbers (in descending order) would be... 975410, 975401 & 975104