You need to know something else to solve: either the long leg or the angle
edit: if it is a right triangle you can use a theorem to figure out the other sides.
the smallest side is a, the hypotenuse is 2a, the longer leg is a * sqrt (3)
if the hypotenuse is 20, the smaller leg is 10.
A hypotenuse should not be shorter than a leg length.
hypotenuse = 18/cos60 = 36
It is 12 units of length.
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2
Hypotenuse = 24
In a 30-60-90 triangle, the hypotenuse is double the length of the shorter leg.
A hypotenuse should not be shorter than a leg length.
The length of the longer leg of a right triangle is 3ftmore than three times the length of the shorter leg. The length of the hypotenuse is 4ftmore than three times the length of the shorter leg. Find the side lengths of the triangle.
hypotenuse = 18/cos60 = 36
If you have the shorter legs length, then for the hypotenuse, just multiply the shorter leg by 2. For the longer leg, multiply the shorter leg by the square root of 3.
A right triangle with a hypotenuse of 40 inches and a side of 8 inches has a leg length of 39.19 inches so the shorter leg IS 8 inches.
If it is a 45-45-90 triangle, then divide the hypotenuse by the square root of 2. If it is a 30-60-90 triangle, then the shorter leg would be the hypotenuse divided by 2. And the longer leg would be the the shorter leg multiplied by the square root of 3.
Using trigonometry and Pythagoras' theorem the length of the hypotenuse is 36
Subtract the squared longer leg's squared length from the hypotenuse's square to obtain the squared shorter leg length. Then find the square root of that answer for your final answer. In other words: 53 squared minus 45 squared equals your squared answer.
It is 12 units of length.
Use the rule that the shortest leg has length p, the other leg has length 2p and the hypotenuse has length p*sqrt(3) Where sqrt(number) if the square root of the number.
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2