Let x be first
Let x+2 be second
Let x+4 be third.
x+x+2+x+4=57
3x+6=57
3x=51
x=17
x+2=19
x+4=21
The perimeter of a triangle is the sum of its 3 sides.
you add up the measures of the sides Perimeter=a+b+c
24 inches You can find the perimeter of a triangle by adding the lengths of all three sides. In this case, since the triangle measures 6, 8, and 10 inches, its perimeter would be the sum of these numbers which is 24 inches.
The perimeter would be 18 cm.
perimeter
The perimeter of a triangle is the sum of its 3 sides.
you add up the measures of the sides Perimeter=a+b+c
24
To find the perimeter of a triangle, add the three sides. Perimeter = 6in + 8in + 10in = 24in.
24 inches You can find the perimeter of a triangle by adding the lengths of all three sides. In this case, since the triangle measures 6, 8, and 10 inches, its perimeter would be the sum of these numbers which is 24 inches.
The perimeter would be 18 cm.
perimeter
24
The sum(addition) of the measures of the three angles of a triangle is 180 degrees.
The angle measures are 59, 60 and 61. Use algebra to figure this out. Let x = the first consecutive number, x + 1 the second and x + 2 the third. So you have x + x + 1 + x + 2 = 180 3x + 3 = 180 3x = 177 x = 59
24 inches is the perimeter
Two measures of a triangle are not sufficient to determine its shape and therefore its perimeter.